x^2+146x-425=0

Solution for x^2+146x-425=0 equation:

x^2+146x-425=0

a = 1; b = 146; c = -425;
Δ = b2-4ac
Δ = 1462-4·1·(-425)
Δ = 23016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{23016}=\sqrt{4*5754}=\sqrt{4}*\sqrt{5754}=2\sqrt{5754}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(146)-2\sqrt{5754}}{2*1}=\frac{-146-2\sqrt{5754}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(146)+2\sqrt{5754}}{2*1}=\frac{-146+2\sqrt{5754}}{2}
$